The
base of the following pyramid is a square. If the volume of the pyramid is 108
in^{3}, what is its surface area? Round the answer to the nearest
hundredth.

The
surface area = in^{2}.

V = 1/3 × s × s × h

h
= (3
× V) / s^{2} = (3 × 108) / 36 = 9 in

l = = 9.49 in

So, SA = s × s + 2 × s × l

= 36 + 2 × 6 × 9.49

=
149.88 in^{2}