If the volume of the cone is 550 in^{3}, what
is its surface area? Use 3.14 for π and round the answer to the nearest hundredth.

The surface area = in^{2}.

V = 1/3 × πr^{2} × h

r^{2} = (3 × V) / (π × h) = (3 × 550) /
(3.14 × 10) = 52.55 in^{2}

r = = 7.25 in

l = = 12.35 in

So, SA = πr^{2} + πrl

= 3.14 × 7.25 × 7.25 + 3.14 × 7.25 × 12.35

= 446.19 in^{2}