Each of the cubes is 1 inch in length. The total
surface area of the solid is inch^{2}.

The left surface’s area is 6 inch^{2}

The front surface’s area is 10 inch^{2}

The top surface’s area is 3 × 4 = 12 inch^{2}

The right surface’s area is 6 inch^{2}

The back surface’s area is 10 inch^{2}

The bottom surface’s area is 3 × 4 = 12 inch^{2}

So, the total surface’s area is 6 + 10 + 12 + 6 + 10 +
12 = 56 inch^{2}