Consider the following balanced equation:

N_{2} + 3H_{2} → 2NH_{3}

How many grams of NH_{3} are produced if 7.0 grams of N_{2} react? (Molar mass of NH_{3} = 17 g/mol, molar mass of N_{2} = 28 g/mol)

g

0.25 mol N_{2} x 2 = 0.50 mol NH_{3}

0.50 mol NH_{3} x 17 g/mol =8.5 g