Solve the following linear system

2*x* – 5 = 0.5*y*

2.5*x = y* + 4

*x* = *y* =

We can first solve for *y* in the first equation, then plug it into the second one to solve for *x*.

2*x* – 5 = 0.5*y*

4*x* – 10 = *y*

2.5*x* = (4*x* – 10) + 4

2.5*x* = 4*x* – 10 + 4

-1.5*x* = -6

*x* = 4

Now we can plug in *x* into either equation and solve for *y*.

2(4) – 5 = 0.5*y*

8 – 5 = 0.5*y*

3 = 0.5*y*

*y* = 6