How much heat will it take to heat 10.0 kg of water from 283 K to 383 K? The boiling point of water is 373 K. The latent heat of vaporization of water is 2260 kJ/kg, and the specific heat of water is 4.2 kJ/kgK.

We will use the formulas Q_{1} = mcΔT, and Q_{2} = mL, and then add them, Q_{1} + Q_{2} = Q_{total}. When we plug in our known values we get that Q_{1} = (10) (4.2) (100) = 4200, and Q_{2} = (10.0) (2260) = 22,600. When we add them together we get Q_{total} = 26800 kJ.