You have an ideal gas in an insulated container. You compress it from a pressure of 50 × 10^{5 }Pa to 25 × 10^{5} Pa, while increasing the volume from 10 to 20 m^{3}. What is the work you did on the gas?

You can solve this by taking the area under the curve. We see from the graph that the area under the curve can be simplified to a rectangle and a triangle. If we take the areas of the two and add them together, we get that they are 380 J.