Sample Problem

Paper has a dielectric constant of 3.70. If capacitor A originally has a capacitance of 0.0400 F, what is its capacitance after paper, a dielectric material, is inserted to completely fill the space between the plates of capacitor A?


Cwith­ dielectric = KCwithout dielectric

K = 3.70

Cwithout dielectric = 0.0400 F

Cwith­ dielectric = 3.70 × 0.0400 F = 0.148 F