Write the equation of a line with slope -5/3 that passes through the point (4, -1). (give your answer in standard y=mx+b form and keep all non-integer values as reduced improper fractions)

y= x +

Use the point-slope formula: (y-y_{1})
= m(x-x_{1}) where (x_{1}, y_{1}) is a point on the
line and m is the slope of the line.

(y-(-1))=(-5/3)(x-4), y+1=(-5/3)x+(20/3)

y=(-5/3)x+(17/3)