Sample Problem

Kenneth throws a ball at an angle of 32° to the horizontal. The vertical component of its velocity  is 20.m/s. What is the magnitude of the total initial velocity vector?



Since the magnitude of vertical component of velocity vector = speed sinθ,

We are given the angle and the vertical component. We can find the magnitude of the vector since sin32 = 20/ vector) ,

thus the vector = 38. m/s