You throw an orange out a window at a height of 12 meters upwards at an angle of 32° to the horizontal at a velocity of 3.5 m/s. It travels for 1.4 seconds before hitting the ground. How far does the orange travel horizontally in total?

The horizontal distance travelled will equal the horizontal component of the velocity vector times the duration of the fall.

Since we know that t = 1.4s , and v = 3.5cos32 = 3.0 m/s,

Thus, the horizontal distance =v t = 4.2 m