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The terminal side of θ lies on the line 7x+12y=0; θ lies in Quadrant II. Find:

sin θ=

7/√193

-12/√193

-7/12

-12/7

cos θ=

7/√193

-12/√193

-7/12

-12/7

tan θ=

7/√193

-12/√193

-7/12

-12/7

sec θ=

√193/7

-√193/12

-7/12

-12/7

csc θ=

√193/7

-12/√193

-7/12

-12/7

cot θ=

7/√193

-12/√193

-7/12

-12/7

Correct!