Find the vector v that has a magnitude of 3 and the same direction as u=<5, 2>.

Find the unit vector with direction u=<5, 2>.

Unit vector of <5, 2>=u/||u||=<5, 2>/<5, 2>/√29=<5/√29, 2/√29>

3*<5/√29, 2/√29>,(<5/√29, 2/√29> has a magnitude of 1 because it is a unit vector)

<15/√[T1] 29, 6/√29> - the vector with magnitude of 3 and direction <5, 2>