Find the vertex of the parabola with the equation (x+4)^{2}=2(y-3/4)

(1/2, -4)

(3/4, 1/2)

(4, -1/2)

(-4, ¾)

To find the vertex, compare this equation (x+4)^{2}=2(y-3/4) (which is already in standard form) to

(x-h)^{2}=4p(y-k)

h=-4

k=3/4

p=1/2

The vertex is at (h, k) – (-4, ¾)