You throw a ball into the air from a height of 5 feet with an initial vertical velocity of 32 feet per second. Use the vertical motion model, h = -16t^{2} + vt + s where v is the initial velocity in feet/second and s is the height in feet, to calculate the maximum height of the ball. Round your answer to the nearest tenth if necessary.^{ }

Maximum height: ^{} feet

h = -16t^{2} + vt + s

h = -16t^{2} + 32t + 5

x-coordinate of vertex: ^{ }= 1

y-coordinate of vertex: h = -16(1)^{2} +32(1) + 5 = 21